Jeff M and Bobweb have the right idea.
The wine cooler has the following electrical requirements.
Running amps = 2.4 A @ 115 V ac
Max Start-up = 5.5 @ 115 V ac
2.4 x 115 = 276 VA.
A 300+ watt converter should work fine.
Using Bob's link: The ST-300 (300 watt) converter is only $40 and is large enough to run the wine cooler. The next size is 500 watts and runs $60.
The "world-import" link below shows smaller and less expensive converters with an internal fuse. The TC-300A (300 watts) unit is rated "for continuous use". You can even buy an upgraded model with built-in voltage regulation for $35.
The losses of this device are not that great, and this is far more efficient that any of the motor/generator or battery/inverter options suggested.
If you can afford to fill a 48 bottle wine cooler, then you can afford the electric bill. Let's assume the voltage converter is only 80% efficient (probably higher). The "losses" of the converter would be:
Input power: 276 ÷ .80 = 345 watts
Output power: 276 watts
Losses = Input - Ouput = 345 - 276 = 69 watts.
69 watts = .069 kW
.069 kW x 24 hours x 365 = 604 kWh
At 10¢ per kWh, that's $60 a year or $5 a month.
You probably spill more than $5 worth a wine a month.
Hongkong has a 50 Hz system, however this 60 Hz device will probably work just fine.
There does not appear to be a dual voltage switch, so you'd need to perform some serious work to replace components with 220 V ones. Make sure you know what you're doing or you could create a safety and/or fire hazzard.