Electronics Fullwave rectification?

Question

if the initial frequency is 60hz, in fullwave rectification would that be 120 Hz or there's a formula to determine the frequency?

I also need to know how to compute for the Ripple voltage, DC voltage and Ripple factor. Links would be helpful but better with explanation

Answer 1

Full wave rectification will produce ripples at

If single phase center tap or bridge = 2 times the input frequency

If 3 phase circuit, 6 diode bridge = 3 times the input frequency

If 3 phase center tap = also 6 diodes = 3F

The ripple voltage is related to the load current and capacitor value



di dt

C= -------

Vc

C is in Farad

Di (delta current) is output current in Amperes

Dt (delta time) is the period between peaks in second

Vc is ripple voltage





Hope this properly answers your question





Guru

Answer 2

Dear pa,

Thank you, am also fine like you then dear what you said is correct that if you apply 60hz in ac side to a full wave rectifier you will get 120hz in output side means the formula is 2times the input frequency

The output dc may contain ripple due to some transients in input side simply this will arrest by put filtering capacitor in correct polarity @ out put side in accord suitable to your rated load current then generally the output voltage DC = 1.414 * input ac voltage

Answer 3

You are right about 120 Hz ripple frequency for single phase 60 Hz power.



The link below shows some circuits and graphics to help understanding.

Answer 4

A full wave rectifier produces 95VDC from 115VAC but has ripple that needs to be smoothed out by an electrolytic capacitor if you want to create DC out of AC. RMS they are the same minus a little tiny bit of loss.