how to convert from dB to volts?

Question

how to convert from dB to volts
like how did we get 2000 from 66dB

Answer 1

First, decibels (dB) is a logarithmic representation of a ratio of either voltage or power, input to output. It is usually used to describe what happens across an amplifier (gain) or restiveness (loss).

If we only know one side, the denominator of the ratio is defined as 1, either 1-Volt or 1-Watt.

The definition of a decibel is a power ratio, so the conversion knowing the watts is:

dB = 10 LOG (Power)



If you know the voltage, then you need to covert to power. To do that, we square voltage (remember voltage squared divided by resistance is power, this may be the key point for your question), mathematically:

dB = 10 LOG (Voltage ** 2)



From our knowledge of logarithms, this can be re-written as:

dB = 20 LOG (Voltage)



To reverse the equation as you to do (from dB, get Volts), divide both sides by 20:

dB/20 = LOG( Voltage)



And then incorporate 10 power to undo the log function:

10**(dB/20) = Voltage



Using 66 for dB comes out close to the 2000 you quoted in the question, but it is not exact because the 66 has been rounded off.

Answer 2

Db To Volts

Answer 3

66 dB = 20(log 2,000). You are using 1 volt as the 0 dB reference point.



To convert 66 dB to a voltage ratio use this formula

X = 10^(66dB/20)

X = 2,000

Answer 4

The initial question is dB to Volts, not Volts to dB. The formula is: antilog (dB/20). You may see it written as log-1(db/20). So for the example provided, ie, 66dB, the answer is log-1 (66/20)= 1995.2623. As a side note, make sure to do the division first and then the antilog.

Answer 5

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RE:

how to convert from dB to volts?

how to convert from dB to volts

like how did we get 2000 from 66dB

Answer 6

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All dB measurements are with respect to a reference, and there are a number of those. If you are using dBµV, which is referenced to 1 µV, then dB = 20 log (17) = 24.6 dBµV where 17 comes from 17µV / 1µV If you are using dBmV, referenced to 1 mV dB = 20 log (17µV/1mV) = –35.4 dBmV

Answer 7

Voltage ratios such as (Vout/Vin) may be expressed in dBs.

To convert a Voltage ratio to dB use this equation

dB = (20)*(log of the Voltage ratio that you wish to convert)

To convert dB back to a Voltage ratio rearrange the equation to;

Voltage ratio = anti log (dB/20)

Therefore;

66 dB can not be converted to a specific Voltage it can only be converted to a specific Voltage ratio.

66dB = 20*(log of a Voltage ratio)

log of that Voltage ratio = 66/20

take anti log of both sides of the equation and get;

that Voltage ratio = anti log (66/20)

that Voltage ratio = 1995.3 (which was rounded off to 2,000 I suppose)

It can therefore be said that if (Vout/Vin) = 1995.3 then Vout is 66 dB greater than Vin.

Answer 8

Decibel Formula