From my understanding, capacitors pass high frequency and act as shorts for very high frequencies based upon 1/(2pi*f*c). I see circuits diagrams with these bypass or decoupling capacitors going to ground. So, my question is, wouldn t a signal with a very high frequency noise (enough to overcome a small capacitance value in the denominator and cause the impedance to become virtually zero) basically be shorted to ground, causing infinite current? I hear people say that "the high frequency will be shorted to ground," but I thought that was bad. Or isn t there ever a circumstance where there will be a frequency high enough?
On another note, is it the first resistor in a passive low pass filter that prevents this from happening through the capacitor in the filter?
Thanks,
Nick