Consider the circuit in the drawing. Determine (a) the magnitude of the current in the circuit and (b) the mag?

Question

Consider the circuit in the drawing. Determine (a) the magnitude of the current in the circuit and (b) the magnitude of the voltage between the points labeled A and B.

http://edugen.wiley.com/edugen/courses/crs1507/art/qb/qu/c20/ch20p_75.gif

Answer 1

I = (30-10) / (27+8+5+12) = 20/52 =0.385 amps



b) can do it either of two ways. easiest is 30 volts – drop across 27 ohm resistor. Latter is E = IR = 0.385 x 27 = 10.38 volts. Vab = 30–10.38 = 19.62 volts.



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Answer 2

Total resistance= 5+27+12+8= 52ohms

Total current in circuit= (30-10)/52= 0.3846Amps.

Voltage drop at 27ohms resistane=27*0.3846= 10.386V

hence voltage between point A and B= 30-10.3846= 19.615V.

Answer 3

The two batteries add up to 20 volts (the polarities are opposite) and the Rs add up to 52 ohms. Current is then 20/52 = 0.385 amps, flowing CW. Vab = –30 + (0.385)(27) = –19.6

Answer 4

resistance = 5+8+12+27 = 52 ohms



current = (30-10)/52 = 0.385 A



(b) 27*0.385 = 10.385 v



V(BA) = 30 - 10.385 = 19.62 v