A basic analog electronics question?

Question

Clamping question...........?
I want to know if the input for a positive biased single silicon diode clamper is Vsin(wt)
The biasing battery has voltage V/2.
What will be exact graph of the output signal?
For what values of sin(wt) will be the diode in forward biased condition?
Is the output exactly sinosuidal?
U can use Wolfram to draw the graph?
If not,then simply describe the output graph for time period T.
You can refer the circuit diagram here.
http://en.wikipedia.org/wiki/File:Positi…
Graph given here is approximate and doesn't answer my question at all.

Answer 1

no circuit diagram in the link !

Answer 2

If battery is 12V then V/2 = 6V. The clamped output will ride on 6V. However, it will keep the valley at 0.6V below 6V due to the necessity for the diode to conduct. Thus a 2V peak sine will appear as though the valley is at 5.4, or the centre is at 6.4V. If the ac amplitude is made 5V, the valley will remain at 5.4, and centre will become 7.9V.

During the time the capacitor charges, the waveform will be distorted. Once that is over, the output will look like a sinusoid..

As seen in circuit maker, the universal (free) simulation tool for students..)

Answer 3

hi

The o/p graph will depend upon the anode connected to supply

see if anode is connected to the supply directly than negative half cycle will be clipped and if the cathode is connected to supply directly + v e half cycle will be clipped.

output voltage will be voltage will be the supply voltage that is yours v/2

the diode will be off for 0.7volts than it will conduct.

Answer 4

basically come across a datasheet for the a/d chip you prefer you have been allowed to apply. be taught the block diagram. Then build each and each block using discrete factors, op-amps, counters, clocks and comparators.

Answer 5

No the graph wont help because no one can see it

Answer 6

is that so